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Welcome to my blog, which was once a mailing list of the same name and is still generated by mail. Please reply via the "comment" links.

Always interested in offers/projects/new ideas. Eclectic experience in fields like: numerical computing; Python web; Java enterprise; functional languages; GPGPU; SQL databases; etc. Based in Santiago, Chile; telecommute worldwide. CV; email.

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© 2006-2017 Andrew Cooke (site) / post authors (content).

Basic HTTP Authentication with XMLRPC in Python

From: "andrew cooke" <andrew@...>

Date: Wed, 31 Dec 2008 17:42:05 -0300 (CLST)

I couldn't find anywhere on the 'net that clearly documented this - there
are various old discussions, but they tend to be out of date.  So here's a
brief sketch of what works.

[Note that HTTP basic authentication - RFC 2617
http://www.faqs.org/rfcs/rfc2617.html - effectively sends username and
password as cleartext.  This is not secure.  As far as I can tell, digest
authentication is not supported, so a more secure (but more complex)
solution would involve SSL (a possible compromise would be basic auth over
SSL, which would only require a server certificate, but which has its own
limitations).]

On the client side, nothing is needed except that username and password
should be placed in the URL used.  The libraries used by xmlrpclib will
construct the correct HTTP header (see below).  So the client code is
simply:

  import xmlrpclib
  server = xmlrpclib.ServerProxy('http://user:pass@...')
  ...

But, obviously, a more typical use case would supply dynamic values.

This generates the Authorization HTTP header, with the format (RFC 2617):

  Authorization: Basic Zm9vOmJhcg==

where Zm9vOmJhcg== is the base64 encoding of, in this case, "foo:bar"
(username and password).  So validation is trivial once this header is
retrieved:

  from base64 import b64decode
  ...
  (basic, _, encoded) = \
    headers.get('Authorization').partition(' ')
  assert basic == 'Basic', 'Only basic authentication supported'
  (username, _, password) = b64decode(encoded).partition(':')
  assert username == 'foo'
  assert password == 'bar'

The only remaining part of the puzzle, then, is how to get the headers. 
Poking around in the source it seems that it is necessary to override
BaseHTTPServer.BaseHTTPRequestHandler.parse_request (which is subclassed
bySimpleXMLRPCServer.SimpleXMLRPCRequestHandler).

So a suitable server class would look like:


  from SimpleXMLRPCServer import SimpleXMLRPCServer, \
    SimpleXMLRPCRequestHandler

  class VerifyingServer(SimpleXMLRPCServer):

    def __init__(self, ..., *args, **kargs):
      # we use an inner class so that we can call out to the
      # authenticate method
      class VerifyingRequestHandler(SimpleXMLRPCRequestHandler):
        # this is the method we must override
        def parse_request(myself):
          # first, call the original implementation which returns
          # True if all OK so far
          if SimpleXMLRPCRequestHandler.parse_request(myself):
            # next we authenticate
            if self.authenticate(myself.headers):
              return True
            else:
              # if authentication fails, tell the client
              myself.send_error(401, 'Authentication failed')
          return False
      # and intialise the superclass with the above
      SimpleXMLRPCServer.__init__(self,
        requestHandler=VerifyingRequestHandler,
        *args, **kargs)

    def authenticate(self, headers):
      # see earlier

Note the distinction between "self" and "myself" above.

Andrew

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